What is the tangent of y=16sqrt(x),(16,64) ?

The tangent of y=16sqrt(x),(16,64) is y=2x+32

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=16sqrt(x),(16,64)

tangent of

y = 16 x, (16, 64)

y = 2 x + 32

Solution steps

Find the slope of

y = 16 x : \frac{d y}{d x} = \frac{8}{x}

Compute the slope of

y = 16 x

(16, 64) : m = 2

Find the line with slope m=

2

and passing through

(16, 64) : y = 2 x + 32

y = 2 x + 32

\frac{d}{d x} (arctan (\frac{3}{x + 2}))

\int \frac{sin ( x )}{2 + cos ( x )} d x

f (x) = (x^{2} + 15) (2 x + 18)

\int \frac{16}{1 + x ^{2}} d x

\frac{d y}{d x} = 2 (1 - y)

What is the tangent of y=16sqrt(x),(16,64) ?
The tangent of y=16sqrt(x),(16,64) is y=2x+32