What is the limit as x approaches 0 of ((sin(7x)))/x ?

The limit as x approaches 0 of ((sin(7x)))/x is 7

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limit as x approaches 0 of ((sin(7x)))/x

x \to 0 lim (\frac{( sin ( 7 x ) )}{x})

7

Solution steps

x \to 0 lim (\frac{sin ( 7 x )}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{cos ( 7 x ) \cdot 7}{1})

= x \to 0 lim (\frac{cos ( 7 x ) \cdot 7}{1})

Plug in the value

x = 0

= \frac{cos ( 7 \cdot 0 ) \cdot 7}{1}

Simplify

\frac{cos ( 7 \cdot 0 ) \cdot 7}{1} : 7

= 7

x^{3}, 3 x + 2

\frac{\partial}{\partial y} (\frac{1}{x y ^{2} z})

\int (x^{2}) ln (x) d x

(e^{- y})^{^{'}}

x \frac{d y}{d x} + x y^{2} = x y

What is the limit as x approaches 0 of ((sin(7x)))/x ?
The limit as x approaches 0 of ((sin(7x)))/x is 7