What is (\partial)/(\partial x)(e^{-7y}cos(7x)) ?

The answer to (\partial)/(\partial x)(e^{-7y}cos(7x)) is -7e^{-7y}sin(7x)

Popular >

(\partial)/(\partial x)(e^{-7y}cos(7x))

\frac{\partial}{\partial x} (e^{- 7 y} cos (7 x))

- 7 e^{- 7 y} sin (7 x)

Solution steps

\frac{\partial}{\partial x} (e^{- 7 y} cos (7 x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= e^{- 7 y} \frac{\partial}{\partial x} (cos (7 x))

Apply the chain rule:

- sin (7 x) \frac{\partial}{\partial x} (7 x)

= - sin (7 x) \frac{\partial}{\partial x} (7 x)

\frac{\partial}{\partial x} (7 x) = 7

= e^{- 7 y} (- sin (7 x) \cdot 7)

Simplify

= - 7 e^{- 7 y} sin (7 x)

\frac{d y}{d x} = \frac{y}{x} + \frac{x}{2 ( y + x )}

\int_{0}^{1} (2 x + 1)^{3} d x

f (x) = 3 x + 7, (3, 4)

\frac{1}{s ( s ^{2} + 2 s + 2 )}

(x - 2)^{2} (x + 4)

What is (\partial)/(\partial x)(e^{-7y}cos(7x)) ?
The answer to (\partial)/(\partial x)(e^{-7y}cos(7x)) is -7e^{-7y}sin(7x)