What is the tangent of f(x)=(5x)/(x+3),(2,2) ?

The tangent of f(x)=(5x)/(x+3),(2,2) is y= 3/5 x+4/5

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tangent of f(x)=(5x)/(x+3),(2,2)

tangent of

f (x) = \frac{5 x}{x + 3}, (2, 2)

y = \frac{3}{5} x + \frac{4}{5}

Solution steps

Find the slope of

f (x) = \frac{5 x}{x + 3} : \frac{df ( x )}{d x} = \frac{15}{( x + 3 ) ^{2}}

Compute the slope of

f (x) = \frac{5 x}{x + 3}

(2, 2) : m = \frac{3}{5}

Find the line with slope m=

\frac{3}{5}

and passing through

(2, 2) : y = \frac{3}{5} x + \frac{4}{5}

y = \frac{3}{5} x + \frac{4}{5}

13.375 ln (\frac{x}{x - 1250})

\int 6 x (1 - x) d x

t^{2} \cdot y^{^{'}} + t y = 7, y (1) = 7

\int 8 sin^{2} (x) cos (x) d x

y^{^{''}} + 2 y^{^{'}} + y = 3 x + 8

What is the tangent of f(x)=(5x)/(x+3),(2,2) ?
The tangent of f(x)=(5x)/(x+3),(2,2) is y= 3/5 x+4/5