What is the derivative of acos(2x+bcos(2x)) ?

The derivative of acos(2x+bcos(2x)) is -2asin(2x)-2bsin(2x)

What is the first derivative of acos(2x+bcos(2x)) ?

The first derivative of acos(2x+bcos(2x)) is -2asin(2x)-2bsin(2x)

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\frac{d}{d x} (a cos (2 x) + b cos (2 x))

- 2 a sin (2 x) - 2 b sin (2 x)

Solution steps

\frac{d}{d x} (a cos (2 x) + b cos (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a cos (2 x)) + \frac{d}{d x} (b cos (2 x))

\frac{d}{d x} (a cos (2 x)) = - 2 a sin (2 x)

\frac{d}{d x} (b cos (2 x)) = - 2 b sin (2 x)

= - 2 a sin (2 x) - 2 b sin (2 x)

\frac{\partial}{\partial x} (y - 5 x)

\int x [2 cos (x) - x sin (x)] d x

x \to 2 lim (6 - 3 x - 3)

\int \frac{1}{1 + 9 x ^{2}} d x

\int \frac{8000 ln ( x + 25 )}{( x + 25 ) ^{2}} d x

What is the derivative of acos(2x+bcos(2x)) ?
The derivative of acos(2x+bcos(2x)) is -2asin(2x)-2bsin(2x)
What is the first derivative of acos(2x+bcos(2x)) ?
The first derivative of acos(2x+bcos(2x)) is -2asin(2x)-2bsin(2x)