What is the d/(dt)(1/(sqrt(t))) ?

The d/(dt)(1/(sqrt(t))) is -1/(2t^{3/2)}

What is the first d/(dt)(1/(sqrt(t))) ?

The first d/(dt)(1/(sqrt(t))) is -1/(2t^{3/2)}

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\frac{d}{d t} (\frac{1}{t})

- \frac{1}{2 t ^{\frac{3}{2}}}

Solution steps

\frac{d}{d t} (\frac{1}{t})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d t} (t^{- \frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - \frac{1}{2} t^{- \frac{1}{2} - 1}

Simplify

- \frac{1}{2} t^{- \frac{1}{2} - 1} : - \frac{1}{2 t ^{\frac{3}{2}}}

= - \frac{1}{2 t ^{\frac{3}{2}}}

\int sec (x) (sec (x) - tan (x)) d x

\int_{0}^{1} 1 + (x)^{2} d x

(x - 3) (x^{2} + 6)

4 x^{3} y + x^{4} y^{^{'}} = - 6 sec^{2} (x) tan (x)

\frac{\partial}{\partial x} (A e^{\frac{1}{x}})

What is the d/(dt)(1/(sqrt(t))) ?
The d/(dt)(1/(sqrt(t))) is -1/(2t^{3/2)}
What is the first d/(dt)(1/(sqrt(t))) ?
The first d/(dt)(1/(sqrt(t))) is -1/(2t^{3/2)}