What is the limit as x approaches 1 of 2/(x^2-1) ?

The limit as x approaches 1 of 2/(x^2-1) is diverges

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limit as x approaches 1 of 2/(x^2-1)

x \to 1 lim (\frac{2}{x ^{2} - 1})

diverges

Solution steps

x \to 1 lim (\frac{2}{x ^{2} - 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim (\frac{2}{x ^{2} - 1}) = \infty

x \to 1 - lim (\frac{2}{x ^{2} - 1}) = - \infty

= diverges

x \to - 0 lim (f (x))

x \to \infty lim ((4^{x} + 3^{x})^{\frac{1}{x}})

\int_{1}^{5} (5 x - \frac{5}{x}) d x

x \to 3 lim (\frac{x - 4}{x - 3})

\int 5 tan (x) sec^{3} (x) d x

What is the limit as x approaches 1 of 2/(x^2-1) ?
The limit as x approaches 1 of 2/(x^2-1) is diverges