What is the tangent of f(x)=(5x-1)^4,\at x=2 ?

The tangent of f(x)=(5x-1)^4,\at x=2 is y=14580x-22599

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=(5x-1)^4,\at x=2

tangent of

f (x) = (5 x - 1)^{4}, at x = 2

y = 14580 x - 22599

Solution steps

Find the tangent point:

(2, 6561)

Find the slope of

f (x) = (5 x - 1)^{4} : \frac{df ( x )}{d x} = 20 (5 x - 1)^{3}

Compute the slope of

f (x) = (5 x - 1)^{4}

x = 2 : m = 14580

Find the line with slope m=

14580

and passing through

(2, 6561) : y = 14580 x - 22599

y = 14580 x - 22599

\frac{\partial}{\partial x} (x^{2} \cdot e^{x})

y = x^{2}, y = \frac{2}{( x ^{2} + 1 )}

\int \frac{1}{x ^{2}} 2 - \frac{1}{x} d x

(19 - (15 - 2 x^{4})^{7})^{3}

(12 x^{2} + y - 1) d x - (6 y - x) d y = 0

What is the tangent of f(x)=(5x-1)^4,\at x=2 ?
The tangent of f(x)=(5x-1)^4,\at x=2 is y=14580x-22599