What is the tangent of f(x)=6x^2+2x-6 ?

The tangent of f(x)=6x^2+2x-6 is y=(12a_{0}+2)x-6a_{0}^2-6

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tangent of f(x)=6x^2+2x-6

tangent of

f (x) = 6 x^{2} + 2 x - 6

y = (12 a_{0} + 2) x - 6 a_{0}^{2} - 6

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 6 a_{0}^{2} + 2 a_{0} - 6)

Find the slope of

f (x) = 6 x^{2} + 2 x - 6 : \frac{df ( x )}{d x} = 12 x + 2

Compute the slope of

f (x) = 6 x^{2} + 2 x - 6

x = a_{0} : m = 12 a_{0} + 2

Find the line with slope m=

12 a_{0} + 2

and passing through

(a_{0}, 6 a_{0}^{2} + 2 a_{0} - 6) : y = (12 a_{0} + 2) x - 6 a_{0}^{2} - 6

y = (12 a_{0} + 2) x - 6 a_{0}^{2} - 6

\frac{d}{d x} (\frac{x + 1}{x - 3})

y = arcsin (6 x + 1)

\frac{d ^{3}}{d x ^{3}} (3 n^{- \frac{1}{3}} + 2 n^{\frac{5}{3}})

\int \frac{1}{- 2 x ^{2} - 12 x + 32} d x

3 t \frac{d y}{d t} + y = t^{4}

What is the tangent of f(x)=6x^2+2x-6 ?
The tangent of f(x)=6x^2+2x-6 is y=(12a_{0}+2)x-6a_{0}^2-6