What is the derivative of sin(1-x) ?

The derivative of sin(1-x) is -cos(1-x)

What is the first derivative of sin(1-x) ?

The first derivative of sin(1-x) is -cos(1-x)

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\frac{d}{d x} (sin (1 - x))

- cos (1 - x)

Solution steps

\frac{d}{d x} (sin (1 - x))

Apply the chain rule:

cos (1 - x) \frac{d}{d x} (1 - x)

= cos (1 - x) \frac{d}{d x} (1 - x)

\frac{d}{d x} (1 - x) = - 1

= cos (1 - x) (- 1)

Simplify

= - cos (1 - x)

\int \frac{sin ( 2 x )}{5 + cos ^{2} ( x )} d x

x \to - \infty lim (- x^{3})

\frac{\partial}{\partial y} (x^{a} y^{1 - a})

\frac{d}{d y} (y + 2 + y \frac{y + 2}{2} - \frac{( y + 2 ) ^{2}}{4})

x \to - 4 lim (x^{2} - 16)

What is the derivative of sin(1-x) ?
The derivative of sin(1-x) is -cos(1-x)
What is the first derivative of sin(1-x) ?
The first derivative of sin(1-x) is -cos(1-x)