What is the derivative of (4x-2^2) ?

The derivative of (4x-2^2) is 8(4x-2)

What is the first derivative of (4x-2^2) ?

The first derivative of (4x-2^2) is 8(4x-2)

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\frac{d}{d x} ((4 x - 2)^{2})

8 (4 x - 2)

Solution steps

\frac{d}{d x} ((4 x - 2)^{2})

Apply the chain rule:

2 (4 x - 2) \frac{d}{d x} (4 x - 2)

= 2 (4 x - 2) \frac{d}{d x} (4 x - 2)

\frac{d}{d x} (4 x - 2) = 4

= 2 (4 x - 2) \cdot 4

Simplify

= 8 (4 x - 2)

\frac{\partial}{\partial s} (\frac{( s - 3 r )}{t})

\frac{d}{d x} (sin^{2} (x) + cos (x))

\int x^{2} 13 x - 1 d x

\int - \frac{1}{2 y} d y

\int - 4 sin^{2} (x) d x

What is the derivative of (4x-2^2) ?
The derivative of (4x-2^2) is 8(4x-2)
What is the first derivative of (4x-2^2) ?
The first derivative of (4x-2^2) is 8(4x-2)