What is the derivative of (1-4t)/(1+3t) ?

The derivative of (1-4t)/(1+3t) is -7/((1+3t)^2)

What is the first derivative of (1-4t)/(1+3t) ?

The first derivative of (1-4t)/(1+3t) is -7/((1+3t)^2)

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derivative of

\frac{1 - 4 t}{1 + 3 t}

- \frac{7}{( 1 + 3 t ) ^{2}}

Solution steps

\frac{d}{d t} (\frac{1 - 4 t}{1 + 3 t})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d t} ( 1 - 4 t ) ( 1 + 3 t ) - \frac{d}{d t} ( 1 + 3 t ) ( 1 - 4 t )}{( 1 + 3 t ) ^{2}}

\frac{d}{d t} (1 - 4 t) = - 4

\frac{d}{d t} (1 + 3 t) = 3

= \frac{( - 4 ) ( 1 + 3 t ) - 3 ( 1 - 4 t )}{( 1 + 3 t ) ^{2}}

Simplify

\frac{( - 4 ) ( 1 + 3 t ) - 3 ( 1 - 4 t )}{( 1 + 3 t ) ^{2}} : - \frac{7}{( 1 + 3 t ) ^{2}}

= - \frac{7}{( 1 + 3 t ) ^{2}}

x \to 1 lim (1 + cos (π) x)

\int_{0}^{1} (2 t - 1)^{2} d t

\frac{d}{d x} (sin^{2} (5 x - 3))

\frac{d y}{d x} + \frac{5}{x} \cdot y = 0

- 8 x^{- 1} + 4 x^{- 2} - 7

What is the derivative of (1-4t)/(1+3t) ?
The derivative of (1-4t)/(1+3t) is -7/((1+3t)^2)
What is the first derivative of (1-4t)/(1+3t) ?
The first derivative of (1-4t)/(1+3t) is -7/((1+3t)^2)