What is the integral from b to 2b of x^4 ?

The integral from b to 2b of x^4 is (31b^5)/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from b to 2b of x^4

\int_{b}^{2 b} x^{4} d x

\frac{31 b ^{5}}{5}

Solution steps

\int_{b}^{2 b} x^{4} d x

Apply the Power Rule

: [\frac{x ^{5}}{5}]_{b}^{2 b}

= [\frac{x ^{5}}{5}]_{b}^{2 b}

Compute the boundaries:

\frac{32 b ^{5}}{5} - \frac{b ^{5}}{5}

= \frac{32 b ^{5}}{5} - \frac{b ^{5}}{5}

Simplify

= \frac{31 b ^{5}}{5}

\frac{d}{d x} (x^{3} e^{- 3 x})

\frac{d}{d x} (5 e^{4 x} - cos^{2} (2 e^{x}))

\int sin^{2} (2 θ) d θ

y^{^{'''}} - 5 y^{^{''}} + 6 y^{^{'}} + 12 y = 0

\frac{d}{d x} (\frac{4}{3} x^{3} + 2)

What is the integral from b to 2b of x^4 ?
The integral from b to 2b of x^4 is (31b^5)/5