What is the derivative of 9x^2-2x+1 ?

The derivative of 9x^2-2x+1 is 18x-2

What is the first derivative of 9x^2-2x+1 ?

The first derivative of 9x^2-2x+1 is 18x-2

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\frac{d}{d x} (9 x^{2} - 2 x + 1)

18 x - 2

Solution steps

\frac{d}{d x} (9 x^{2} - 2 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 x^{2}) - \frac{d}{d x} (2 x) + \frac{d}{d x} (1)

\frac{d}{d x} (9 x^{2}) = 18 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 18 x - 2 + 0

Simplify

= 18 x - 2

x sin (\frac{4}{x})

\int_{0}^{1} 2 π (x) (x - x^{2}) d x

\frac{d}{d x} (lo g_{7} (\frac{x ^{4}}{5 x + 11}))

x^{2} (1 - 4 x)

\frac{d}{d x} (x (x^{3} + 1)^{\frac{1}{3}})

What is the derivative of 9x^2-2x+1 ?
The derivative of 9x^2-2x+1 is 18x-2
What is the first derivative of 9x^2-2x+1 ?
The first derivative of 9x^2-2x+1 is 18x-2