What is the integral of (tan^2(x)4) ?

The integral of (tan^2(x)4) is 4(-x+tan(x))+C

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integral of (tan^2(x)4)

\int (tan^{2} (x) 4) d x

4 (- x + tan (x)) + C

Solution steps

\int tan^{2} (x) \cdot 4 d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int tan^{2} (x) d x

Rewrite using trig identities

= 4 \cdot \int - 1 + sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 4 (- \int 1 d x + \int sec^{2} (x) d x)

\int 1 d x = x

\int sec^{2} (x) d x = tan (x)

= 4 (- x + tan (x))

Add a constant to the solution

= 4 (- x + tan (x)) + C

\frac{d}{d x} (e^{2 x^{6}} - 1)

\frac{\partial}{\partial y} (ln (x^{6} + y^{7}))

x \to 6 - lim (cos (\frac{1}{x - 6}))

\frac{\partial}{\partial y} (x^{2} + y^{2} + x y)

\frac{d}{d x} (\frac{10}{( 1 - x ) ^{3}})

What is the integral of (tan^2(x)4) ?
The integral of (tan^2(x)4) is 4(-x+tan(x))+C