What is the derivative of 2^t ?

The derivative of 2^t is 2^tln(2)

What is the first derivative of 2^t ?

The first derivative of 2^t is 2^tln(2)

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derivative of

2^{t}

2^{t} ln (2)

Solution steps

\frac{d}{d t} (2^{t})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 2^{t} ln (2)

\int \frac{8 x - 2}{x ^{2} - 1} d x

\int e^{9 x} d x

x \to 2 lim (x + 6)

\frac{d}{d t} (x ln (t))

y = x^{3} - x, y = 3 x, - 2, 2