What is the integral from 1 to 3 of \sqrt[3]{x}(x-4) ?

The integral from 1 to 3 of \sqrt[3]{x}(x-4) is (27\sqrt[3]{3}-3)/7-9\sqrt[3]{3}+3

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integral from 1 to 3 of \sqrt[3]{x}(x-4)

Decimal Notation

- 4.84585 \dots

Solution steps

Expand

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

Simplify

\frac{d y}{d x}, e^{4 x} = sin (x + 5 y)

\frac{e ^{x}}{1 + x}

y^{^{''}} - 4 y^{^{'}} + 6 y = e^{3 x} - 21

\int \frac{sin ( x )}{1 + cos ^{2} ( x )} d x

\int (e^{- x} - e^{3}) (e^{x} + e^{- 5}) d x

What is the integral from 1 to 3 of \sqrt[3]{x}(x-4) ?
The integral from 1 to 3 of \sqrt[3]{x}(x-4) is (27\sqrt[3]{3}-3)/7-9\sqrt[3]{3}+3