What is the sum from n=0 to infinity of (1.67)^n ?

The sum from n=0 to infinity of (1.67)^n is diverges

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sum from n=0 to infinity of (1.67)^n

n = 0 \sum \infty (1.67)^{n}

diverges

Solution steps

n = 0 \sum \infty 1.6 7^{n}

Apply Series Geometric Test:

diverges

= diverges

\frac{d y}{d x}, y^{9} = x^{8}

\int (x^{2} - 8)^{3} (2 x) d x

\int_{1}^{\infty} x^{- 7} d x

\frac{d}{d x} (\frac{x + 2}{x ^{2} + 4 x + 13})

n = 1 \sum \infty \frac{60}{7 ^{n}}

What is the sum from n=0 to infinity of (1.67)^n ?
The sum from n=0 to infinity of (1.67)^n is diverges