en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=x^3,(1,1)

Solution

tangent of

y = x^{3}, (1, 1)

Solution

y = 3 x - 2

Solution steps

Find the slope of

y = x^{3} : \frac{d y}{d x} = 3 x^{2}

Compute the slope of

y = x^{3}

at

(1, 1) : m = 3

Find the line with slope m=

3

and passing through

(1, 1) : y = 3 x - 2

y = 3 x - 2

Popular Examples

d/(dt)(-1/(t+1))

\frac{d}{d t} (- \frac{1}{t + 1})

derivative of (x/(x+1)^5)

\frac{d}{d x} ((\frac{x}{x + 1})^{5})

limit as t approaches 0 of (sin(kt))/t

t \to 0 lim (\frac{sin ( k t )}{t})

derivative of f(x)= x/a derivative of

f (x) = \frac{x}{a}

tangent of f(x)=x^2(4-x)^2,\at x=1 tangent of

f (x) = x^{2} (4 - x)^{2}, at x = 1

Frequently Asked Questions (FAQ)

What is the tangent of y=x^3,(1,1) ?
The tangent of y=x^3,(1,1) is y=3x-2