What is (\partial)/(\partial x)(6x^2+7y) ?

The answer to (\partial)/(\partial x)(6x^2+7y) is 12x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(6x^2+7y)

\frac{\partial}{\partial x} (6 x^{2} + 7 y)

12 x

Solution steps

\frac{\partial}{\partial x} (6 x^{2} + 7 y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (6 x^{2}) + \frac{\partial}{\partial x} (7 y)

\frac{\partial}{\partial x} (6 x^{2}) = 12 x

\frac{\partial}{\partial x} (7 y) = 0

= 12 x + 0

Simplify

= 12 x

\frac{d}{d x} (∣ x ∣^{3} - x^{2})

x \to \infty lim (\frac{12 x ^{3} - 4 x + 1}{1 + 3 x + 2 x ^{3}})

\frac{8 x - 7}{5 x + 12}

\frac{d}{d x} (f (x) (x)^{- 1} (a x))

\frac{d}{d t} (t^{2} - 1)

What is (\partial)/(\partial x)(6x^2+7y) ?
The answer to (\partial)/(\partial x)(6x^2+7y) is 12x