What is the integral of x/(2y^4) ?

The integral of x/(2y^4) is (x^2)/(4y^4)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of x/(2y^4)

\int \frac{x}{2 y ^{4}} d x

\frac{x ^{2}}{4 y ^{4}} + C

Solution steps

\int \frac{x}{2 y ^{4}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2 y ^{4}} \cdot \int x d x

Apply the Power Rule

: \frac{x ^{2}}{2}

= \frac{1}{2 y ^{4}} \cdot \frac{x ^{2}}{2}

Simplify

\frac{1}{2 y ^{4}} \cdot \frac{x ^{2}}{2} : \frac{x ^{2}}{4 y ^{4}}

= \frac{x ^{2}}{4 y ^{4}}

Add a constant to the solution

= \frac{x ^{2}}{4 y ^{4}} + C

\frac{d}{d x} (\frac{3 sin ( x )}{2 + cos ( x )})

\int_{0}^{2} 4 t d t

f (x) = \frac{4 x - 3}{5 x ^{2} + 3 x}

\int x sin^{3} (x) d x