What is the derivative of x^3-4x ?

The derivative of x^3-4x is 3x^2-4

What is the first derivative of x^3-4x ?

The first derivative of x^3-4x is 3x^2-4

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\frac{d}{d x} (x^{3} - 4 x)

3 x^{2} - 4

Solution steps

\frac{d}{d x} (x^{3} - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (4 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (4 x) = 4

= 3 x^{2} - 4

\frac{d ^{3}}{d x ^{3}} (\frac{7}{x ^{2}})

\frac{\partial}{\partial x} (a^{x})

\int \frac{5 x}{( x ^{2} + 5 ) ^{2}} d x

\frac{d}{d x} (- cos (\frac{x}{2}))

\frac{- 6 x}{( x ^{2} + 1 )}

What is the derivative of x^3-4x ?
The derivative of x^3-4x is 3x^2-4
What is the first derivative of x^3-4x ?
The first derivative of x^3-4x is 3x^2-4