What is the integral from 1 to 11 of 1/(x-7) ?

The integral from 1 to 11 of 1/(x-7) is diverges

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integral from 1 to 11 of 1/(x-7)

\int_{1}^{11} \frac{1}{x - 7} d x

diverges

Solution steps

\int_{1}^{11} \frac{1}{x - 7} d x

Find undefined (singularity) points:

x = 7

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{1}^{7} \frac{1}{x - 7} d x + \int_{7}^{11} \frac{1}{x - 7} d x

\int_{1}^{7} \frac{1}{x - 7} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\frac{d}{d x} ((x + 5 x) (x^{\frac{3}{2}} - x))

f (x) = 3 x^{4} - 12 x^{3} + 4

(1 + x^{2})^{\frac{1}{2}}

\int 3 x^{2} cos (x^{3} + 2) d x

\int 9 e^{0.01 x} d x

What is the integral from 1 to 11 of 1/(x-7) ?
The integral from 1 to 11 of 1/(x-7) is diverges