What is the solution for y^'+y/t =t^2y^4 ?

The solution for y^'+y/t =t^2y^4 is y=\sqrt[3]{1/(t^3(-3ln(t)+c_{1))}}

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y^'+y/t =t^2y^4

y^{^{'}} + \frac{y}{t} = t^{2} y^{4}

Solution steps

y^{'} (t) + \frac{y}{t} = t^{2} y^{4}

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What is the solution for y^'+y/t =t^2y^4 ?
The solution for y^'+y/t =t^2y^4 is y=\sqrt[3]{1/(t^3(-3ln(t)+c_{1))}}