What is the derivative of (x^3/6-(3x^2)/2) ?

The derivative of (x^3/6-(3x^2)/2) is (x^2)/2-3x

What is the first derivative of (x^3/6-(3x^2)/2) ?

The first derivative of (x^3/6-(3x^2)/2) is (x^2)/2-3x

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\frac{d}{d x} (\frac{x ^{3}}{6} - \frac{3 x ^{2}}{2})

\frac{x ^{2}}{2} - 3 x

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{6} - \frac{3 x ^{2}}{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{6}) - \frac{d}{d x} (\frac{3 x ^{2}}{2})

\frac{d}{d x} (\frac{x ^{3}}{6}) = \frac{x ^{2}}{2}

\frac{d}{d x} (\frac{3 x ^{2}}{2}) = 3 x

= \frac{x ^{2}}{2} - 3 x

\int 1.2

\int sin^{3} (3 x) cos (3 x) d x

\int sec^{2} (x) csc^{2} (x) d x

\int_{0}^{\infty} e^{- x t} d t

\int 16 t^{3} d t

What is the derivative of (x^3/6-(3x^2)/2) ?
The derivative of (x^3/6-(3x^2)/2) is (x^2)/2-3x
What is the first derivative of (x^3/6-(3x^2)/2) ?
The first derivative of (x^3/6-(3x^2)/2) is (x^2)/2-3x