What is the derivative of y=(3x^2+3x-1)^4 ?

The derivative of y=(3x^2+3x-1)^4 is 4(3x^2+3x-1)^3(6x+3)

What is the first derivative of y=(3x^2+3x-1)^4 ?

The first derivative of y=(3x^2+3x-1)^4 is 4(3x^2+3x-1)^3(6x+3)

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derivative of

y = (3 x^{2} + 3 x - 1)^{4}

4 (3 x^{2} + 3 x - 1)^{3} (6 x + 3)

Solution steps

\frac{d}{d x} ((3 x^{2} + 3 x - 1)^{4})

Apply the chain rule:

4 (3 x^{2} + 3 x - 1)^{3} \frac{d}{d x} (3 x^{2} + 3 x - 1)

= 4 (3 x^{2} + 3 x - 1)^{3} \frac{d}{d x} (3 x^{2} + 3 x - 1)

\frac{d}{d x} (3 x^{2} + 3 x - 1) = 6 x + 3

= 4 (3 x^{2} + 3 x - 1)^{3} (6 x + 3)

(x^{2} - 3 y^{2}) d x + (2 x y) d y = 0

\frac{d}{d x} (\frac{x}{x})

f (x) = 4 x^{2} - 4 x + 1, (- 1, 8)

\frac{\partial}{\partial x} (y - \frac{27}{x ^{2}})

\int (2 sin (x) - 5 e^{x}) d x

What is the derivative of y=(3x^2+3x-1)^4 ?
The derivative of y=(3x^2+3x-1)^4 is 4(3x^2+3x-1)^3(6x+3)
What is the first derivative of y=(3x^2+3x-1)^4 ?
The first derivative of y=(3x^2+3x-1)^4 is 4(3x^2+3x-1)^3(6x+3)