What is the derivative of x^2-8x+13 ?

The derivative of x^2-8x+13 is 2x-8

What is the first derivative of x^2-8x+13 ?

The first derivative of x^2-8x+13 is 2x-8

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\frac{d}{d x} (x^{2} - 8 x + 13)

2 x - 8

Solution steps

\frac{d}{d x} (x^{2} - 8 x + 13)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (8 x) + \frac{d}{d x} (13)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (13) = 0

= 2 x - 8 + 0

Simplify

= 2 x - 8

\frac{d}{d x} (\frac{2 x}{x ^{2}})

y^{3} - (10 x + 4) + 3 x y^{2} y^{^{'}} = 0

(3 a + 1)^{2}

\int_{1}^{9} x ln (x) d x

\int \frac{cos ( a ) x}{b + sin ( a ) x} d x

What is the derivative of x^2-8x+13 ?
The derivative of x^2-8x+13 is 2x-8
What is the first derivative of x^2-8x+13 ?
The first derivative of x^2-8x+13 is 2x-8