What is area y=3-x,y=2x^2,[0,1] ?

The answer to area y=3-x,y=2x^2,[0,1] is 11/6

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area y=3-x,y=2x^2,[0,1]

area

y = 3 - x, y = 2 x^{2}, [0, 1]

\frac{11}{6}

Decimal Notation

1.83333 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} 3 - x - 2 x^{2} d x

Solve

\int_{0}^{1} 3 - x - 2 x^{2} d x : \frac{11}{6}

The area is:

= \frac{11}{6}

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