What is area y=x^2-2,y=((3x+1))/2 ?

The answer to area y=x^2-2,y=((3x+1))/2 is 343/48

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area y=x^2-2,y=((3x+1))/2

area

y = x^{2} - 2, y = \frac{( 3 x + 1 )}{2}

\frac{343}{48}

Decimal Notation

7.14583 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{\frac{5}{2}} x^{2} - 2 - \frac{1}{2} (3 x + 1) d x

Solve

\int_{- 1}^{\frac{5}{2}} x^{2} - 2 - \frac{1}{2} (3 x + 1) d x : \frac{343}{48}

The area is:

= \frac{343}{48}

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What is area y=x^2-2,y=((3x+1))/2 ?
The answer to area y=x^2-2,y=((3x+1))/2 is 343/48