What is (\partial)/(\partial x)(6x^2cos(y^7)) ?

The answer to (\partial)/(\partial x)(6x^2cos(y^7)) is 12xcos(y^7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(6x^2cos(y^7))

\frac{\partial}{\partial x} (6 x^{2} cos (y^{7}))

12 x cos (y^{7})

Solution steps

\frac{\partial}{\partial x} (6 x^{2} cos (y^{7}))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 cos (y^{7}) \frac{\partial}{\partial x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 6 cos (y^{7}) \cdot 2 x^{2 - 1}

Simplify

= 12 x cos (y^{7})

y = \frac{8 x ^{2} + 6 x + 2}{x}

\int_{1}^{5} 5 d x

x \to 0 lim (\frac{1}{x + 2})

x \to 0 + lim (x^{3})

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2}}{1 + e ^{x}})

What is (\partial)/(\partial x)(6x^2cos(y^7)) ?
The answer to (\partial)/(\partial x)(6x^2cos(y^7)) is 12xcos(y^7)