What is the limit as x approaches 5 of 7/(x-5) ?

The limit as x approaches 5 of 7/(x-5) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 5 of 7/(x-5)

x \to 5 lim (\frac{7}{x - 5})

diverges

Solution steps

x \to 5 lim (\frac{7}{x - 5})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 5 + lim (\frac{7}{x - 5}) = \infty

x \to 5 - lim (\frac{7}{x - 5}) = - \infty

= diverges

x \to \infty lim (7 + \frac{4}{x})

n = 1 \sum \infty \frac{3 n}{2 n + 1}

\frac{\partial}{\partial x} (\frac{y}{x ^{2} + y ^{2} + 1})

6 x y^{^{'}} = 2 x e^{x} - 6 y + 6 x^{2}

\frac{\partial}{\partial v} (u^{2})

What is the limit as x approaches 5 of 7/(x-5) ?
The limit as x approaches 5 of 7/(x-5) is diverges