What is the derivative of (x^3^5) ?

The derivative of (x^3^5) is 15x^{14}

What is the first derivative of (x^3^5) ?

The first derivative of (x^3^5) is 15x^{14}

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\frac{d}{d x} ((x^{3})^{5})

15 x^{14}

Solution steps

\frac{d}{d x} ((x^{3})^{5})

Simplify

(x^{3})^{5} : x^{15}

= \frac{d}{d x} (x^{15})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 15 x^{15 - 1}

Simplify

= 15 x^{14}

\int \frac{1}{u 2 - u ^{2}} d u

n = 1 \sum \infty \frac{1}{2}

n = 0 \sum \infty 1 + \frac{1}{n}

y^{^{'}} - \frac{y}{x} = x

What is the derivative of (x^3^5) ?
The derivative of (x^3^5) is 15x^{14}
What is the first derivative of (x^3^5) ?
The first derivative of (x^3^5) is 15x^{14}