What is the derivative of f(x)=((2-e^x+2x))/3 ?

The derivative of f(x)=((2-e^x+2x))/3 is 1/3 (-e^x+2)

What is the first derivative of f(x)=((2-e^x+2x))/3 ?

The first derivative of f(x)=((2-e^x+2x))/3 is 1/3 (-e^x+2)

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derivative of

f (x) = \frac{( 2 - e ^{x} + 2 x )}{3}

\frac{1}{3} (- e^{x} + 2)

Solution steps

\frac{d}{d x} (\frac{2 - e ^{x} + 2 x}{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{d}{d x} (2 - e^{x} + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{3} (\frac{d}{d x} (2) - \frac{d}{d x} (e^{x}) + \frac{d}{d x} (2 x))

\frac{d}{d x} (2) = 0

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (2 x) = 2

= \frac{1}{3} (0 - e^{x} + 2)

Simplify

= \frac{1}{3} (- e^{x} + 2)

\int x y d x

(7, - 7), (5, - 3)

(- 6, - 5), (2, - 10)

h \to 0 lim (\frac{( cos ( x + h ) - cos ( x ) )}{h})

n = 0 \sum \infty 3 x^{2 n + 1}

What is the derivative of f(x)=((2-e^x+2x))/3 ?
The derivative of f(x)=((2-e^x+2x))/3 is 1/3 (-e^x+2)
What is the first derivative of f(x)=((2-e^x+2x))/3 ?
The first derivative of f(x)=((2-e^x+2x))/3 is 1/3 (-e^x+2)