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Popular >

derivative of ((5t+300))/(t^2)+25

Solution

derivative of

\frac{( 5 t + 300 )}{t ^{2}} + 25

Solution

\frac{5 ( - t - 120 )}{t ^{3}}

Solution steps

\frac{d}{d t} (\frac{5 t + 300}{t ^{2}} + 25)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (\frac{5 t + 300}{t ^{2}}) + \frac{d}{d t} (25)

\frac{d}{d t} (\frac{5 t + 300}{t ^{2}}) = \frac{5 ( - t - 120 )}{t ^{3}}

\frac{d}{d t} (25) = 0

= \frac{5 ( - t - 120 )}{t ^{3}} + 0

Simplify

= \frac{5 ( - t - 120 )}{t ^{3}}

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Frequently Asked Questions (FAQ)

What is the derivative of ((5t+300))/(t^2)+25 ?
The derivative of ((5t+300))/(t^2)+25 is (5(-t-120))/(t^3)
What is the first derivative of ((5t+300))/(t^2)+25 ?
The first derivative of ((5t+300))/(t^2)+25 is (5(-t-120))/(t^3)