What is area y= 1/2 x^3+2,y=x+1,x=0,x=1 ?

The answer to area y= 1/2 x^3+2,y=x+1,x=0,x=1 is 5/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area y= 1/2 x^3+2,y=x+1,x=0,x=1

area

y = \frac{1}{2} x^{3} + 2, y = x + 1, x = 0, x = 1

\frac{5}{8}

Decimal Notation

0.625

Solution steps

Apply the area formula:

\int_{0}^{1} \frac{1}{2} x^{3} + 2 - (x + 1) d x

Solve

\int_{0}^{1} \frac{1}{2} x^{3} + 2 - (x + 1) d x : \frac{5}{8}

The area is:

= \frac{5}{8}

\int \frac{2}{( x ^{2} + 1 ) ( x + 1 )} d x

\frac{\partial}{\partial x} (e^{x^{2} + y^{2} + 2 y + 5})

x \to 2 lim (\frac{- 2 x ^{2}}{x - 2})

\int (x - \frac{2}{x}) d x

x \to 0 lim (x^{2} - 8 x + 9)

What is area y= 1/2 x^3+2,y=x+1,x=0,x=1 ?
The answer to area y= 1/2 x^3+2,y=x+1,x=0,x=1 is 5/8