What is the integral from 1 to 6 of 1/x ?

The integral from 1 to 6 of 1/x is ln(6)

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integral from 1 to 6 of 1/x

\int_{1}^{6} \frac{1}{x} d x

ln (6)

Decimal Notation

1.79175 \dots

Solution steps

\int_{1}^{6} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{1}^{6}

Compute the boundaries:

ln (6)

= ln (6)

\int \frac{1}{x ( x ^{4} - 1 )} d x

(2 x y - 9 x^{2}) d x + (2 y + x^{2} + 1) d y = 0

\int \frac{4 x}{x ^{2} + 2 x - 3} d x

f (x) = tan (x), at x = 0

y^{^{'''}} + y^{^{''}} - 8 y^{^{'}} - 12 y = 0

What is the integral from 1 to 6 of 1/x ?
The integral from 1 to 6 of 1/x is ln(6)