What is the derivative of y=sin(x)+xcos(x) ?

The derivative of y=sin(x)+xcos(x) is 2cos(x)-xsin(x)

What is the first derivative of y=sin(x)+xcos(x) ?

The first derivative of y=sin(x)+xcos(x) is 2cos(x)-xsin(x)

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derivative of

y = sin (x) + x cos (x)

2 cos (x) - x sin (x)

Solution steps

\frac{d}{d x} (sin (x) + x cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (x)) + \frac{d}{d x} (x cos (x))

\frac{d}{d x} (sin (x)) = cos (x)

\frac{d}{d x} (x cos (x)) = cos (x) - x sin (x)

= cos (x) + cos (x) - x sin (x)

Simplify

= 2 cos (x) - x sin (x)

\int_{0}^{5} \frac{1}{x ^{\frac{19}{18}}} d x

f (x) = \frac{3}{x ^{2}}, (1, 3)

\frac{d}{d x} ((9 x - 6)^{2})

\int \frac{1}{10 + 4 x - x ^{2}} d x

\int - \frac{2 x y}{( x ^{2} + y ^{2} ) ^{2}} d y

What is the derivative of y=sin(x)+xcos(x) ?
The derivative of y=sin(x)+xcos(x) is 2cos(x)-xsin(x)
What is the first derivative of y=sin(x)+xcos(x) ?
The first derivative of y=sin(x)+xcos(x) is 2cos(x)-xsin(x)