What is the derivative of 2000(1-x/(600))^2 ?

The derivative of 2000(1-x/(600))^2 is -20/3 (1-x/(600))

What is the first derivative of 2000(1-x/(600))^2 ?

The first derivative of 2000(1-x/(600))^2 is -20/3 (1-x/(600))

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derivative of

2000 (1 - \frac{x}{600})^{2}

- \frac{20}{3} (1 - \frac{x}{600})

Solution steps

\frac{d}{d x} (2000 (1 - \frac{x}{600})^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2000 \frac{d}{d x} ((1 - \frac{x}{600})^{2})

Apply the chain rule:

2 (1 - \frac{x}{600}) \frac{d}{d x} (1 - \frac{x}{600})

= 2 (1 - \frac{x}{600}) \frac{d}{d x} (1 - \frac{x}{600})

\frac{d}{d x} (1 - \frac{x}{600}) = - \frac{1}{600}

= 2000 \cdot 2 (1 - \frac{x}{600}) (- \frac{1}{600})

Simplify

2000 \cdot 2 (1 - \frac{x}{600}) (- \frac{1}{600}) : - \frac{20}{3} (1 - \frac{x}{600})

= - \frac{20}{3} (1 - \frac{x}{600})

\frac{d}{d x} (ln (x^{2} + 19))

\int \frac{3}{6 x - x ^{2}} d x

f (x) = 5 x + 6, at a = 2

\frac{d}{d x} (ln (x^{2} - 14 x))

2 x^{2} - 80 x + y^{2} + 49 = 0 (0)

What is the derivative of 2000(1-x/(600))^2 ?
The derivative of 2000(1-x/(600))^2 is -20/3 (1-x/(600))
What is the first derivative of 2000(1-x/(600))^2 ?
The first derivative of 2000(1-x/(600))^2 is -20/3 (1-x/(600))