What is (\partial)/(\partial x)(sin(-x)cos(4y)) ?

The answer to (\partial)/(\partial x)(sin(-x)cos(4y)) is -cos(4y)cos(x)

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(\partial)/(\partial x)(sin(-x)cos(4y))

\frac{\partial}{\partial x} (sin (- x) cos (4 y))

- cos (4 y) cos (x)

Solution steps

\frac{\partial}{\partial x} (sin (- x) cos (4 y))

Simplify

sin (- x) cos (4 y) : - sin (x) cos (4 y)

= \frac{\partial}{\partial x} (- sin (x) cos (4 y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - cos (4 y) \frac{\partial}{\partial x} (sin (x))

Apply the common derivative:

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= - cos (4 y) cos (x)

y^{^{'}} = 2 y + x e^{x}, y (0) = - 1

\frac{55}{0.01 x ^{2} + 1}

\int tan^{4} (4 t) d t

\frac{\partial}{\partial y} (x y + ln (x + y))

y = 2 x e^{x}, (0, 0)

What is (\partial)/(\partial x)(sin(-x)cos(4y)) ?
The answer to (\partial)/(\partial x)(sin(-x)cos(4y)) is -cos(4y)cos(x)