What is the derivative of 4x(sin(x+cos(x))) ?

The derivative of 4x(sin(x+cos(x))) is 4(sin(x)+cos(x)+x(cos(x)-sin(x)))

What is the first derivative of 4x(sin(x+cos(x))) ?

The first derivative of 4x(sin(x+cos(x))) is 4(sin(x)+cos(x)+x(cos(x)-sin(x)))

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\frac{d}{d x} (4 x (sin (x) + cos (x)))

4 (sin (x) + cos (x) + x (cos (x) - sin (x)))

Solution steps

\frac{d}{d x} (4 x (sin (x) + cos (x)))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x (sin (x) + cos (x)))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x, g = sin (x) + cos (x)

= 4 (\frac{d x}{d x} (sin (x) + cos (x)) + \frac{d}{d x} (sin (x) + cos (x)) x)

\frac{d x}{d x} = 1

\frac{d}{d x} (sin (x) + cos (x)) = cos (x) - sin (x)

= 4 (1 \cdot (sin (x) + cos (x)) + (cos (x) - sin (x)) x)

Simplify

= 4 (sin (x) + cos (x) + x (cos (x) - sin (x)))

\frac{\partial}{\partial x} (x y + b^{x y})

\frac{d y}{d x} = \frac{x - 1}{y ^{3}}

x \to + 2 lim (\frac{( 1 )}{( x + 2 )})

\frac{d}{d x} ((e^{2 x})^{2})

\frac{d}{d x} (\frac{4 - x}{5 x})

What is the derivative of 4x(sin(x+cos(x))) ?
The derivative of 4x(sin(x+cos(x))) is 4(sin(x)+cos(x)+x(cos(x)-sin(x)))
What is the first derivative of 4x(sin(x+cos(x))) ?
The first derivative of 4x(sin(x+cos(x))) is 4(sin(x)+cos(x)+x(cos(x)-sin(x)))