What is the integral of ((ln(x))^{32})/x ?

The integral of ((ln(x))^{32})/x is (ln^{33}(x))/(33)+C

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integral of ((ln(x))^{32})/x

\int \frac{( ln ( x ) ) ^{32}}{x} d x

\frac{ln ^{33} ( x )}{33} + C

Solution steps

\int \frac{( ln ( x ) ) ^{32}}{x} d x

Apply u-substitution

: \int u^{32} d u

= \int u^{32} d u

Apply the Power Rule

: \frac{u ^{33}}{33}

= \frac{u ^{33}}{33}

Substitute back

u = ln (x)

= \frac{ln ^{33} ( x )}{33}

Add a constant to the solution

= \frac{ln ^{33} ( x )}{33} + C

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What is the integral of ((ln(x))^{32})/x ?
The integral of ((ln(x))^{32})/x is (ln^{33}(x))/(33)+C