What is the derivative of x^3-6x^2+8x ?

The derivative of x^3-6x^2+8x is 3x^2-12x+8

What is the first derivative of x^3-6x^2+8x ?

The first derivative of x^3-6x^2+8x is 3x^2-12x+8

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\frac{d}{d x} (x^{3} - 6 x^{2} + 8 x)

3 x^{2} - 12 x + 8

Solution steps

\frac{d}{d x} (x^{3} - 6 x^{2} + 8 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (6 x^{2}) + \frac{d}{d x} (8 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (8 x) = 8

= 3 x^{2} - 12 x + 8

y^{^{''}} + 4 y = 8 x^{2}

x^{3} + y^{3} = 9

\int (7 x^{2}) e x^{3} + 1 d x

f (x) = - 4 sin (4 x)

(- 4, - 2), (5, - 7)

What is the derivative of x^3-6x^2+8x ?
The derivative of x^3-6x^2+8x is 3x^2-12x+8
What is the first derivative of x^3-6x^2+8x ?
The first derivative of x^3-6x^2+8x is 3x^2-12x+8