What is the derivative of (x-3)(x^2+6) ?

The derivative of (x-3)(x^2+6) is 3x^2-6x+6

What is the first derivative of (x-3)(x^2+6) ?

The first derivative of (x-3)(x^2+6) is 3x^2-6x+6

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derivative of

(x - 3) (x^{2} + 6)

3 x^{2} - 6 x + 6

Solution steps

\frac{d}{d x} ((x - 3) (x^{2} + 6))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x - 3, g = x^{2} + 6

= \frac{d}{d x} (x - 3) (x^{2} + 6) + \frac{d}{d x} (x^{2} + 6) (x - 3)

\frac{d}{d x} (x - 3) = 1

\frac{d}{d x} (x^{2} + 6) = 2 x

= 1 \cdot (x^{2} + 6) + 2 x (x - 3)

Simplify

1 \cdot (x^{2} + 6) + 2 x (x - 3) : 3 x^{2} - 6 x + 6

= 3 x^{2} - 6 x + 6

\frac{\partial}{\partial x} (8 x cos (x) cos (y))

x \to 1 lim (\frac{∣ x ∣}{x})

x \to 0 lim (h (\frac{1}{x}))

\int e^{θ} sin (3 θ) d θ

\int 5 x^{3} e^{x^{4}} d x

What is the derivative of (x-3)(x^2+6) ?
The derivative of (x-3)(x^2+6) is 3x^2-6x+6
What is the first derivative of (x-3)(x^2+6) ?
The first derivative of (x-3)(x^2+6) is 3x^2-6x+6