What is the tangent of x^2y^2=4,(-1,2) ?

The tangent of x^2y^2=4,(-1,2) is y=2x+4

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tangent of x^2y^2=4,(-1,2)

tangent of

x^{2} y^{2} = 4, (- 1, 2)

y = 2 x + 4

Solution steps

Find the slope of

x^{2} y^{2} = 4 : \frac{d y}{d x} = - \frac{y}{x}

Compute the slope of

x^{2} y^{2} = 4

(- 1, 2) : m = 2

Find the line with slope m=

2

and passing through

(- 1, 2) : y = 2 x + 4

y = 2 x + 4

\int 4 - 25 x^{2} d x

\frac{d}{d x} (ln (\frac{x}{4}) + \frac{x - 4}{x})

f (x) = \frac{x ^{2} - 10 x + 25}{x - 5}

(9.11) (- 8.9)

\frac{\partial}{\partial x} (4 y x)

What is the tangent of x^2y^2=4,(-1,2) ?
The tangent of x^2y^2=4,(-1,2) is y=2x+4