What is the derivative of f(x)=(4x^2-5x)e^x ?

The derivative of f(x)=(4x^2-5x)e^x is 4e^xx^2+3e^xx-5e^x

What is the first derivative of f(x)=(4x^2-5x)e^x ?

The first derivative of f(x)=(4x^2-5x)e^x is 4e^xx^2+3e^xx-5e^x

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derivative of

f (x) = (4 x^{2} - 5 x) e^{x}

4 e^{x} x^{2} + 3 e^{x} x - 5 e^{x}

Solution steps

\frac{d}{d x} ((4 x^{2} - 5 x) e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = 4 x^{2} - 5 x, g = e^{x}

= \frac{d}{d x} (4 x^{2} - 5 x) e^{x} + \frac{d}{d x} (e^{x}) (4 x^{2} - 5 x)

\frac{d}{d x} (4 x^{2} - 5 x) = 8 x - 5

\frac{d}{d x} (e^{x}) = e^{x}

= (8 x - 5) e^{x} + e^{x} (4 x^{2} - 5 x)

Simplify

(8 x - 5) e^{x} + e^{x} (4 x^{2} - 5 x) : 4 e^{x} x^{2} + 3 e^{x} x - 5 e^{x}

= 4 e^{x} x^{2} + 3 e^{x} x - 5 e^{x}

\int 5 e^{- 4 x} d x

\frac{d}{d x} (arcsin (\frac{9}{x ^{2}}))

(\frac{4 x}{x ^{2} + 1})^{\frac{1}{4}}

f (x) = 4 x + 2

\int \frac{( y )}{( 1 + y ^{(2)} )} d y

What is the derivative of f(x)=(4x^2-5x)e^x ?
The derivative of f(x)=(4x^2-5x)e^x is 4e^xx^2+3e^xx-5e^x
What is the first derivative of f(x)=(4x^2-5x)e^x ?
The first derivative of f(x)=(4x^2-5x)e^x is 4e^xx^2+3e^xx-5e^x