What is the integral from 0 to 0.5 of 3000x ?

The integral from 0 to 0.5 of 3000x is 375

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integral from 0 to 0.5 of 3000x

\int_{0}^{0.5} 3000 x d x

375

Solution steps

\int_{0}^{0.5} 3000 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3000 \cdot \int_{0}^{0.5} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.5}

= 3000 [\frac{x ^{2}}{2}]_{0}^{0.5}

Simplify

= 3000 [0.5 x^{2}]_{0}^{0.5}

Compute the boundaries:

0.125

= 3000 \cdot 0.125

Simplify

= 375

\frac{d}{d x} (x^{2} sec (x))

\frac{d}{d x} (e^{\frac{2}{3} x})

\int y e^{y x} d x

\int \frac{4}{u} d u

x \to \infty lim (k^{x} c)

What is the integral from 0 to 0.5 of 3000x ?
The integral from 0 to 0.5 of 3000x is 375