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Popular >

y^'=8x+y

Solution

y^{^{'}} = 8 x + y

Solution

y = - 8 (x + 1) + c_{1} e^{x}

Solution steps

y^{'} (x) = 8 x + y

Solve linear ODE:

y = - 8 (x + 1) + c_{1} e^{x}

y = - 8 (x + 1) + c_{1} e^{x}

Popular Examples

tangent of y=6sqrt(x),(9,18)tangent of

y = 6 x, (9, 18)

(\partial)/(\partial x)(yarctan(x))

\frac{\partial}{\partial x} (y arctan (x))

limit as x approaches 0 of (sin(x))/(2x)

x \to 0 lim (\frac{sin ( x )}{2 x})

derivative of 2cos(x+2xsin(x))

\frac{d}{d x} (2 cos (x) + 2 x sin (x))

(dy)/(dx)+y=2x^2

\frac{d y}{d x} + y = 2 x^{2}

Frequently Asked Questions (FAQ)

What is the solution for y^'=8x+y ?
The solution for y^'=8x+y is y=-8(x+1)+c_{1}e^x