What is the derivative of 60x^4-160x^3+120x^2-20 ?

The derivative of 60x^4-160x^3+120x^2-20 is 240x^3-480x^2+240x

What is the first derivative of 60x^4-160x^3+120x^2-20 ?

The first derivative of 60x^4-160x^3+120x^2-20 is 240x^3-480x^2+240x

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\frac{d}{d x} (60 x^{4} - 160 x^{3} + 120 x^{2} - 20)

240 x^{3} - 480 x^{2} + 240 x

Solution steps

\frac{d}{d x} (60 x^{4} - 160 x^{3} + 120 x^{2} - 20)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (60 x^{4}) - \frac{d}{d x} (160 x^{3}) + \frac{d}{d x} (120 x^{2}) - \frac{d}{d x} (20)

\frac{d}{d x} (60 x^{4}) = 240 x^{3}

\frac{d}{d x} (160 x^{3}) = 480 x^{2}

\frac{d}{d x} (120 x^{2}) = 240 x

\frac{d}{d x} (20) = 0

= 240 x^{3} - 480 x^{2} + 240 x - 0

Simplify

= 240 x^{3} - 480 x^{2} + 240 x

\frac{d}{d x} ((11 x^{2} - 22 x + 22) e^{x})

\int 3 4 x - 7 d x

\frac{\partial}{\partial y} (ln (x^{2} + y^{2}) - z)

(2 + y) d x - (3 - x) d y = 0

\frac{d y}{d x} = \frac{2 x y}{x ^{2} - y ^{2}}

What is the derivative of 60x^4-160x^3+120x^2-20 ?
The derivative of 60x^4-160x^3+120x^2-20 is 240x^3-480x^2+240x
What is the first derivative of 60x^4-160x^3+120x^2-20 ?
The first derivative of 60x^4-160x^3+120x^2-20 is 240x^3-480x^2+240x