What is the integral of-4e^x ?

The integral of-4e^x is -4e^x+C

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integral of-4e^x

\int - 4 e^{x} d x

- 4 e^{x} + C

Solution steps

\int - 4 e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 4 \cdot \int e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= - 4 e^{x}

Add a constant to the solution

= - 4 e^{x} + C

\int_{0}^{2} 2 π x (3 x (x - 2)^{2}) d x

n = 1 \sum \infty \frac{2 n}{3 n - 1}

\frac{d}{d x} (\frac{3 a}{4 x ^{5}})

\frac{x ^{2} + 4 x}{( 2 + x ) ^{2}}

ln (1 - 2 x)