What is (\partial)/(\partial x)(2x-3yz) ?

The answer to (\partial)/(\partial x)(2x-3yz) is 2

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(\partial)/(\partial x)(2x-3yz)

\frac{\partial}{\partial x} (2 x - 3 yz)

2

Solution steps

\frac{\partial}{\partial x} (2 x - 3 yz)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x) - \frac{\partial}{\partial x} (3 yz)

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (3 yz) = 0

= 2 - 0

Simplify

= 2

\int_{0}^{1} (7 x^{e} + 2 e^{x}) d x

\frac{d y}{d x} = x x - 27

9 x - 6 x, at x = 1

\int csc^{4} (x) cot^{4} (x) d x

What is (\partial)/(\partial x)(2x-3yz) ?
The answer to (\partial)/(\partial x)(2x-3yz) is 2